Chapter 103 of 2363 min read

Law of mass action, Kc and Kp, Le Chatelier

Why this is asked: Kp and Kc are related by a factor of (RT) raised to the power Δn — moles of gaseous product minus reactant — and getting that exponent's sign backwards inverts the whole conversion. Separately, adding an inert gas at constant volume leaves equilibrium untouched, but adding it at constant pressure shifts it toward the side with more gas moles, because the container must expand to keep pressure fixed.

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Test yourself

•For the reaction $A (g) ⇌ 2B (g)$ , the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500 at 1000 K. [Given $R = 0.0831 L atm mo l^{- 1} K^{- 1}$ .] $K_{p}$ for the reaction at 1000 K is:
•A higher yield of NO in $N_{2} (g) + O_{2} (g) ⇌ 2NO (g)$ can be obtained at [ $Δ H$ of the reaction $= + 180.7 kJ mo l^{- 1}$ ]: A. Higher temperature · B. Lower temperature · C. Higher concentration of $N_{2}$ · D. Higher concentration of $O_{2}$ Choose the correct answer from the options given below:
•In which of the following equilibria are $K_{p}$ and $K_{c}$ not equal?

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