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ChemistryNEET 2019Solubility product and common-ion effect

Equilibrium

The pH of a saturated solution of Ca(OH)2\mathrm{Ca(OH)_2} is 9. The solubility product (KspK_{sp}) of Ca(OH)2\mathrm{Ca(OH)_2} is:

  1. A.0.5×10−150.5 \times 10^{-15}✓
  2. B.0.25×10−100.25 \times 10^{-10}
  3. C.0.125×10−150.125 \times 10^{-15}
  4. D.0.5×10−100.5 \times 10^{-10}

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