ChemistryNEET 2019Solubility product and common-ion effect

Equilibrium

The pH of a saturated solution of $Ca (OH)_{2}$ is 9. The solubility product ( $K_{s p}$ ) of $Ca (OH)_{2}$ is:

A. $0.5 \times 1 0^{- 15}$ ✓
B. $0.25 \times 1 0^{- 10}$
C. $0.125 \times 1 0^{- 15}$
D. $0.5 \times 1 0^{- 10}$

You have the answer. The worked solution — and why the other three were written — is part of a paid pack.

More from this chapter in past papers

Find the solubility of {Ni(OH) 2} in 0.1 M NaOH. Given that the ionic product of {Ni(OH)…NEET 2020

From Chemistry › Equilibrium › Solubility product and common-ion effect — lectures, notes and every past question on it.

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