PhysicsNEET 2021Projectile motion

Motion in a Plane

A particle moving in a circle of radius $R$ with a uniform speed takes a time $T$ to complete one revolution. If this particle were projected with the same speed at an angle $θ$ to the horizontal, the maximum height attained by it equals $4 R$ . The angle of projection $θ$ is then given by:

A. $θ = cos^{- 1} (\frac{g T ^{2}}{π ^{2} R})^{1/2}$
B. $θ = cos^{- 1} (\frac{π ^{2} R}{g T ^{2}})^{1/2}$
C. $θ = sin^{- 1} (\frac{π ^{2} R}{g T ^{2}})^{1/2}$
D. $θ = sin^{- 1} (\frac{2 g T ^{2}}{π ^{2} R})^{1/2}$ ✓

You have the answer. The worked solution — and why the other three were written — is part of a paid pack.

Motion in a Plane

More from this chapter in past papers