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PhysicsNEET 2024Young's, bulk and shear moduli; Poisson's ratio

Mechanical Properties of Solids

The maximum elongation of a steel wire of 1 m length, if the elastic limit of steel and its Young's modulus are respectively 8×108 N m−28 \times 10^{8}\ \mathrm{N\,m^{-2}} and 2×1011 N m−22 \times 10^{11}\ \mathrm{N\,m^{-2}}, is:

  1. A.0.4 mm
  2. B.40 mm
  3. C.8 mm
  4. D.4 mm✓

Solution

At the elastic limit, strain =stressY=8×1082×1011=4×10−3= \frac{\text{stress}}{Y} = \frac{8\times10^8}{2\times10^{11}} = 4\times10^{-3}. Elongation =strain×L=4×10−3×1= \text{strain} \times L = 4\times10^{-3} \times 1 m =4= 4 mm.

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