Skip to content
PhysicsNEET 2024Connected bodies, pulleys and pseudo forces

Laws of Motion

A horizontal force of 10 N is applied to a block A, which is in contact with a block B on the side away from the force. The masses of blocks A and B are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is:

  1. A.4 N
  2. B.6 N✓
  3. C.10 N
  4. D.Zero

Solution

Both blocks share acceleration a=102+3=2a = \frac{10}{2+3} = 2 m/s2m/s^{2}. The only horizontal force on B is the push from A: F=mBa=3×2=6F = m_B a = 3 \times 2 = 6 N.

Save for spaced revision (free account)

More from this chapter in past papers

From Physics › Laws of Motion › Connected bodies, pulleys and pseudo forces — lectures, notes and every past question on it.

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram