A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (take g = 9.8\

Question

A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (take g = 9.8\ \mathrm{m/s^2}):

Vishal Gupta · Accepted Answer

A. Speed just before impact = \sqrt{2g	imes40} = 28 m/s downward; just after = \sqrt{2g	imes10} = 14 m/s upward. Impulse = m\Delta v = 0.5 	imes (14 + 28) = 21 N s.

Laws of Motion

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