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PhysicsNEET 2025Newton's laws, inertia, impulse and momentum

Laws of Motion

A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (take g=9.8 m/s2g = 9.8\ \mathrm{m/s^2}):

  1. A.21 N s✓
  2. B.7 N s
  3. C.0
  4. D.84 N s

Solution

Speed just before impact =2g×40=28= \sqrt{2g\times40} = 28 m/s downward; just after =2g×10=14= \sqrt{2g\times10} = 14 m/s upward. Impulse =mΔv=0.5×(14+28)=21= m\Delta v = 0.5 \times (14 + 28) = 21 N s.

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