The ratio of the wavelengths of the light absorbed by a hydrogen atom when it undergoes the n = 2 \rightarrow n = 3 and n = 4 \rightarrow n = 6 transitions, respectively, is:

Question

Vishal Gupta · Accepted Answer

D. \frac{1}{\lambda} \propto \frac{1}{n1^2} - \frac{1}{n2^2}. For 2	o3: \frac14 - \frac19 = \frac{5}{36}. For 4	o6: \frac{1}{16} - \frac{1}{36} = \frac{5}{144}. So \frac{\lambda{2	o3}}{\lambda{4	o6}} = \frac{5/144}{5/36} = \frac{1}{4}.

Structure of Atom

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