PhysicsNEET 2021Moment of inertia, theorems of axes

System of Particles and Rotational Motion

From a circular ring of mass $M$ and radius $R$ an arc corresponding to a 90° sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is $K$ times $M R^{2}$ . Then the value of $K$ is:

A. $\frac{3}{4}$ ✓
B. $\frac{7}{8}$
C. $\frac{1}{4}$
D. $\frac{1}{8}$

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System of Particles and Rotational Motion

More from this chapter in past papers