Skip to content
ChemistryNEET 2022Stoichiometry and limiting reagent

Some Basic Concepts of Chemistry

What mass of 95% pure CaCO3\mathrm{CaCO_3} will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? (Calculate up to the second place of decimal.)

CaCO3(s)+2HCl(aq)→CaCl2(aq)+CO2(g)+2H2O(l)\mathrm{CaCO_3(s) + 2HCl(aq) \rightarrow CaCl_2(aq) + CO_2(g) + 2H_2O(l)}

  1. A.9.50 g
  2. B.1.25 g
  3. C.1.32 g✓
  4. D.3.65 g

You have the answer. The worked solution — and why the other three were written — is part of a paid pack.

More from this chapter in past papers

From Chemistry › Some Basic Concepts of Chemistry › Stoichiometry and limiting reagent — lectures, notes and every past question on it.

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram