ChemistryNEET 2024Stoichiometry and limiting reagent

Some Basic Concepts of Chemistry

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution. The mass of sodium hydroxide left unreacted is equal to:

A.250 mg✓
B.Zero mg
C.200 mg
D.750 mg

Solution

1 g NaOH $= \frac{1}{40} = 0.025$ mol. HCl supplied $= 0.025 \times 0.75 = 0.01875$ mol. NaOH left $= 0.025 - 0.01875 = 0.00625$ mol $= 0.25$ g $= 250$ mg.

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