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ChemistryNEET 2024Stoichiometry and limiting reagent

Some Basic Concepts of Chemistry

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution. The mass of sodium hydroxide left unreacted is equal to:

  1. A.250 mg✓
  2. B.Zero mg
  3. C.200 mg
  4. D.750 mg

Solution

1 g NaOH =140=0.025= \frac{1}{40} = 0.025 mol. HCl supplied =0.025×0.75=0.01875= 0.025 \times 0.75 = 0.01875 mol. NaOH left =0.025−0.01875=0.00625= 0.025 - 0.01875 = 0.00625 mol =0.25= 0.25 g =250= 250 mg.

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