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PhysicsNEET 2024Matter waves and de Broglie wavelength

Dual Nature of Radiation and Matter

The graph which shows the variation of 1λ2\dfrac{1}{\lambda^2} with the kinetic energy EE of a free particle (where λ\lambda is its de Broglie wavelength) is:

Question 18 as printed in the NEET 2024 booklet

  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)✓
  4. D.Graph (4)

Solution

λ=h2mE⇒1λ2=2mEh2\lambda = \frac{h}{\sqrt{2mE}} \Rightarrow \frac{1}{\lambda^2} = \frac{2mE}{h^2}, which is directly proportional to EE: a straight line through the origin.

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