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PhysicsNEET 2024Ohm's law, resistivity, temperature dependence

Current Electricity

A wire of length ll and resistance 100 Ω100\ \Omega is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:

  1. A.52Ω52 \Omega✓
  2. B.55Ω55 \Omega
  3. C.60Ω60 \Omega
  4. D.26Ω26 \Omega

Solution

Each part is 10Ω10 \Omega. Five in series give 50Ω50 \Omega; five in parallel give 2Ω2 \Omega; the two groups in series give 50+2=5250 + 2 = 52 Ω\Omega.

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