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ChemistryNEET 2024Molecular orbital theory

Chemical Bonding and Molecular Structure

Match List I with List II.

List I (Molecule) List II (Number and type of bonds between two carbon atoms)
A. ethane I. one σ\sigma-bond and two π\pi-bonds
B. ethene II. two π\pi-bonds
C. carbon molecule, C2\mathrm{C_2} III. one σ\sigma-bond
D. ethyne IV. one σ\sigma-bond and one π\pi-bond

Choose the correct answer from the options given below:

  1. A.A-IV, B-III, C-II, D-I
  2. B.A-III, B-IV, C-II, D-I✓
  3. C.A-III, B-IV, C-I, D-II
  4. D.A-I, B-IV, C-II, D-III

Solution

Ethane: one C–CσC \sigma bond (III). Ethene: one σ\sigma and one π(\pi (IV). Ethyne: one σ\sigma and two π(I)\pi (I). By molecular orbital theory the C2\mathrm{C_2} molecule has a double bond made of two π\pi bonds only (II). Hence A-III, B-IV, C-II, D-I.

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