Skip to content
ChemistryNEET 2024Arrhenius equation and activation energy

Chemical Kinetics

Which plot of ln⁡k\ln k vs 1T\dfrac{1}{T} (from the four graphs shown) is consistent with the Arrhenius equation?

Question 85 as printed in the NEET 2024 booklet

  1. A.Graph (1)
  2. B.Graph (2)
  3. C.Graph (3)✓
  4. D.Graph (4)

Solution

Arrhenius: ln⁡k=ln⁡A−EaR⋅1T\ln k = \ln A - \dfrac{E_a}{R}\cdot\dfrac1T. A plot of ln⁡k\ln k against 1/T1/T is a straight line with negative slope −Ea/R-E_a/R and positive intercept ln⁡A\ln A — graph (3).

Save for spaced revision (free account)

More from this chapter in past papers

From Chemistry › Chemical Kinetics › Arrhenius equation and activation energy — lectures, notes and every past question on it.

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram