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PhysicsNEET 2025Self and mutual inductance

Electromagnetic Induction

AB is a part of an electrical circuit (see figure). The potential difference VA−VBV_A - V_B, at the instant when the current i=2i = 2 A and is increasing at a rate of 1 A/s, is:

Question 11 as printed in the NEET 2025 booklet

  1. A.5 volt
  2. B.6 volt
  3. C.9 volt
  4. D.10 volt✓

Solution

Walk from A to B adding potential drops: across the inductor Ldidt=1×1=1L\dfrac{di}{dt} = 1 \times 1 = 1 V (current increasing); across the cell, entering at the positive plate, a drop of 5 V; across the resistor iR=2×2=4iR = 2 \times 2 = 4 V. VA−VB=1+5+4=10V_A - V_B = 1 + 5 + 4 = 10 V.

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