Skip to content
PhysicsNEET 2025Spring–mass system and simple pendulum

Oscillations

In an oscillating spring–mass system, a spring is connected to a box filled with sand. As the box oscillates, sand leaks slowly out of the box vertically so that the average frequency ω(t)\omega(t) and average amplitude A(t)A(t) of the system change with time tt. Which one of the following options (graphs shown) schematically depicts these changes correctly?

Question 23 as printed in the NEET 2025 booklet

  1. A.Graph (1)
  2. B.Graph (2)✓
  3. C.Graph (3)
  4. D.Graph (4)

Solution

ω=k/m\omega = \sqrt{k/m}, so as sand leaves and mm falls, ω\omega rises and levels off. Each grain that leaves carries away its share of the kinetic energy, so the oscillator's energy 12kA2\tfrac12 kA^2 decreases and the amplitude falls — option (2).

Save for spaced revision (free account)

More from this chapter in past papers

From Physics › Oscillations › Spring–mass system and simple pendulum — lectures, notes and every past question on it.

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram