Skip to content
PhysicsNEET 2025Kirchhoff's rules, Wheatstone bridge, potentiometer

Current Electricity

A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is:

Question 36 as printed in the NEET 2025 booklet

  1. A.1.5 A
  2. B.2.0 A✓
  3. C.2.5 A
  4. D.3.0 A

Solution

C and D are joined by a wire, so they are at a common potential VV (take VA=0V_A = 0, VB=50V_B = 50 V). Current balance at that node: V1+V3=50−V2+50−V4⇒4V3=3(50−V)4⇒V=18\dfrac{V}{1} + \dfrac{V}{3} = \dfrac{50 - V}{2} + \dfrac{50 - V}{4} \Rightarrow \dfrac{4V}{3} = \dfrac{3(50 - V)}{4} \Rightarrow V = 18 V. Into C through 1Ω1 \Omega: 18 A; out of C through 2Ω2 \Omega: 16 A. The difference, 2.0 A, flows along CD.

Save for spaced revision (free account)

More from this chapter in past papers

From Physics › Current Electricity › Kirchhoff's rules, Wheatstone bridge, potentiometer — lectures, notes and every past question on it.

Last revised . Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsAppTelegram