If the rate constant of a reaction is 0.03\ \mathrm{s^{-1}}, how much time does it take for a 7.2\ \mathrm{mol\,L^{-1}} concentration of the reactant to get reduced to 0.9\ \mathrm{mol\,L^{-1}}? (Give

Question

If the rate constant of a reaction is 0.03\ \mathrm{s^{-1}}, how much time does it take for a 7.2\ \mathrm{mol\,L^{-1}} concentration of the reactant to get reduced to 0.9\ \mathrm{mol\,L^{-1}}? (Given \log 2 = 0.301)

Vishal Gupta · Accepted Answer

A. A rate constant in \mathrm{s^{-1}} means first order. t = \frac{2.303}{k}\log\frac{[A]0}{[A]} = \frac{2.303}{0.03}\log 8 = \frac{2.303 	imes 3 	imes 0.301}{0.03} \approx 69.3 s.

Chemical Kinetics

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