Chapter 4 of 2363 min read

Displacement, velocity, acceleration; graphs

Why this is asked: Area under a v-t graph gives displacement, not distance — where the graph dips below the axis that area subtracts, so total distance needs the positive and negative areas summed separately, not net.

This chapter is part of a paid pack

A sample of the book is free to read — the rest, including this chapter, unlocks with full access.

See pricing

Test yourself

•In some appropriate units, the time ( $t$ ) and position ( $x$ ) relation of a moving particle is given by $t = x^{2} + x$ . The acceleration of the particle is:
•The velocity ( $v$ )–time ( $t$ ) plot of the motion of a body is shown below. The acceleration ( $a$ )–time ( $t$ ) graph that best suits this motion is:

Open this in the full syllabus view · Physics

ShareWhatsApp Telegram