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PhysicsNEET 2024Cells, EMF, internal resistance, combinations

Current Electricity

Two heaters A and B have power ratings of 1 kW and 2 kW, respectively. The two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:

  1. A.2 : 9✓
  2. B.1 : 2
  3. C.2 : 3
  4. D.1 : 1

Solution

Series: Ps=P1P2P1+P2=23P_s = \frac{P_1 P_2}{P_1 + P_2} = \frac{2}{3} kW. Parallel: Pp=P1+P2=3P_p = P_1 + P_2 = 3 kW. Ratio =2/33=29= \frac{2/3}{3} = \frac{2}{9}.

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