PhysicsNEET 2024Cells, EMF, internal resistance, combinations

Current Electricity

The terminal voltage of a battery whose emf is 10 V and internal resistance $1 Ω$ , when connected through an external resistance of $4 Ω$ , is:

A.6 V
B.8 V✓
C.10 V
D.4 V

Solution

Current $I = \frac{ε}{R + r} = \frac{10}{4 + 1} = 2$ A. Terminal voltage $V = ε - I r = 10 - 2 = 8$ V.

Save for spaced revision (free account)

More from this chapter in past papers

Two heaters A and B have power ratings of 1 kW and 2 kW…NEET 2024
10 resistors, each of resistance R, are connected in series to a battery of emf E and…NEET 2023
Six similar bulbs, each of resistance R, are connected to a DC source of emf E (zero…NEET 2019

From Physics › Current Electricity › Cells, EMF, internal resistance, combinations — lectures, notes and every past question on it.

Last revised 7 Sept 2026. Found a mistake? Tell us — corrections are the fastest thing we act on.

ShareWhatsApp Telegram