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PhysicsNEET 2019Simple harmonic motion: equations, energy

Oscillations

The displacement of a particle executing simple harmonic motion is given by y=A0+Asin⁡ωt+Bcos⁡ωty = A_0 + A\sin\omega t + B\cos\omega t. Then the amplitude of its oscillation is given by:

  1. A.A0+A2+B2A_0 + \sqrt{A^2+B^2}
  2. B.A2+B2\sqrt{A^2+B^2}✓
  3. C.A02+(A+B)2\sqrt{A_0^2+(A+B)^2}
  4. D.A+BA+B

You have the answer. The worked solution — and why the other three were written — is part of a paid pack.

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