PhysicsNEET 2024Simple harmonic motion: equations, energy

Oscillations

If $x = 5 sin (π t + \frac{π}{3})$ m represents the motion of a particle executing simple harmonic motion, the amplitude and time period of the motion, respectively, are:

A.5 m, 2 s✓
B.5 cm, 1 s
C.5 m, 1 s
D.5 cm, 2 s

Solution

Comparing with $x = A sin (ω t + ϕ)$ : amplitude $A = 5$ m and $ω = π$ rad/s, so $T = \frac{2 π}{ω} = 2$ s.

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