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PhysicsNEET 2019Simple harmonic motion: equations, energy

Oscillations

A particle P moves in a circle of radius 3 m, centred at the origin in the xyxy-plane, with period T=4T = 4 s. At t=0t = 0, P is at the topmost point of the circle (maximum yy-displacement). The yy-projection of the position vector of P, as a function of time, is:

  1. A.y(t)=−3cos⁡2πty(t) = -3\cos 2\pi t m
  2. B.y(t)=4sin⁡(πt2)y(t) = 4\sin\left(\dfrac{\pi t}{2}\right) m
  3. C.y(t)=3cos⁡(3πt2)y(t) = 3\cos\left(\dfrac{3\pi t}{2}\right) m
  4. D.y(t)=3cos⁡(πt2)y(t) = 3\cos\left(\dfrac{\pi t}{2}\right) m✓

You have the answer. The worked solution — and why the other three were written — is part of a paid pack.

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