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NEET 2025Zoology

All 45 Zoology questions we hold from this paper, of the 178 on the site for this sitting — every option and the answer key. 4 marks each, −1 for a wrong answer.

Zoology

45 questions, one correct option each. +4 for a correct answer, −1 for a wrong one, nothing for a blank.

Q1openBiotechnology: Principles and Processes · Tools of recombinant DNA technology

Given below are two statements:

Statement I: The DNA fragments extracted from gel electrophoresis can be used in the construction of recombinant DNA.

Statement II: Smaller-size DNA fragments are observed near the anode while larger fragments are found near the wells in an agarose gel.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both Statement I and Statement II are correct
  2. B.Both Statement I and Statement II are incorrect
  3. C.Statement I is correct but Statement II is incorrect
  4. D.Statement I is incorrect but Statement II is correct

Solution

DNA bands cut from an agarose gel and eluted are used to build recombinant DNA (I correct). DNA is negative and moves towards the anode; smaller fragments travel farthest, so they lie nearer the anode while large ones stay near the wells (II correct).

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Q2openBiomolecules · Nucleic acids

Match List I with List II.

List IList II
A. AdenosineI. Nitrogen base
B. Adenylic acidII. Nucleotide
C. AdenineIII. Nucleoside
D. AlanineIV. Amino acid

Choose the option with all correct matches:

  1. A.A-III, B-IV, C-II, D-I
  2. B.A-III, B-II, C-IV, D-I
  3. C.A-III, B-II, C-I, D-IV
  4. D.A-II, B-III, C-I, D-IV

Solution

Adenosine is a nucleoside (III), adenylic acid a nucleotide (II), adenine a nitrogen base (I) and alanine an amino acid (IV).

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Q3openHuman Reproduction · Gametogenesis and menstrual cycle

Consider the following:

A. The reductive division for human female gametogenesis starts earlier than that of male gametogenesis.

B. The gap between the first meiotic division and the second meiotic division is much shorter for males compared to females.

C. The first polar body is associated with the formation of the primary oocyte.

D. The luteinising hormone (LH) surge leads to disintegration of the endometrium and onset of menstrual bleeding.

Choose the correct answer from the options given below:

  1. A.A and B are true
  2. B.A and C are true
  3. C.B and D are true
  4. D.B and C are true

Solution

Oogenesis begins in the foetal ovary, long before spermatogenesis starts at puberty (A true). In males meiosis I and II follow each other quickly; in females meiosis I halts before birth and meiosis II completes only at fertilisation (B true). The first polar body accompanies the secondary oocyte (C false); the LH surge triggers ovulation, not menstruation (D false). Hence A and B.

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Q4openAnimal Kingdom · Chordates: Pisces to Mammalia

All living members of the class Cyclostomata are:

  1. A.Free living
  2. B.Endoparasites
  3. C.Symbiotic
  4. D.Ectoparasites

Solution

All living cyclostomes (lampreys and hagfishes) are ectoparasites on some fishes, attaching with their sucking mouths.

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Q5openCell: The Unit of Life · Cell membrane, cell wall and endomembrane system

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): The primary function of the Golgi apparatus is to package the materials made by the endoplasmic reticulum and deliver them to intracellular targets and outside the cell.

Reason (R): Vesicles containing materials made by the endoplasmic reticulum fuse with the cis face of the Golgi apparatus, and they are modified and released from the trans face of the Golgi apparatus.

In the light of the above statements, choose the correct answer from the options given below:

  1. A.Both A and R are true and R is the correct explanation of A
  2. B.Both A and R are true but R is not the correct explanation of A
  3. C.A is true but R is false
  4. D.A is false but R is true

Solution

Packaging and delivering ER products is the Golgi's principal job (A true), and material does arrive in vesicles at the cis face and leave, modified, from the trans face (R true) — R describes how A is achieved.

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Q6openSexual Reproduction in Flowering Plants · Post-fertilisation: embryo, seed, fruit; apomixis

Match List I with List II.

List IList II
A. ScutellumI. Persistent nucellus
B. Non-albuminous seedII. Cotyledon of monocot seed
C. EpiblastIII. Groundnut
D. PerispermIV. Rudimentary cotyledon

Choose the option with all correct matches:

  1. A.A-II, B-III, C-IV, D-I
  2. B.A-IV, B-III, C-II, D-I
  3. C.A-IV, B-III, C-I, D-II
  4. D.A-II, B-IV, C-III, D-I

Solution

The scutellum is the single cotyledon of a grass seed (II); groundnut is a non-albuminous seed (III); the epiblast is a rudimentary cotyledon in some monocot embryos (IV); perisperm is persistent nucellus (I).

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Q7openAnimal Kingdom · Basis of classification

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): All vertebrates are chordates but all chordates are not vertebrates.

Reason (R): The members of subphylum Vertebrata possess a notochord during the embryonic period; the notochord is replaced by a cartilaginous or bony vertebral column in adults.

In the light of the above statements, choose the correct answer from the options given below:

  1. A.Both (A) and (R) are true and (R) is the correct explanation of (A)
  2. B.Both (A) and (R) are true but (R) is not the correct explanation of (A)
  3. C.(A) is true but (R) is false
  4. D.(A) is false but (R) is true

Solution

Vertebrata is a subphylum of Chordata, so every vertebrate is a chordate but tunicates and cephalochordates are chordates that never form a vertebral column (A true). Vertebrates keep the notochord only as embryos, replacing it with a vertebral column (R true), which is exactly what separates them from the other chordates.

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Q8openHuman Health and Disease · Immunity, vaccination, AIDS, cancer

Identify the statement that is not correct.

  1. A.Each antibody has two light and two heavy chains.
  2. B.The heavy and light chains are held together by disulfide bonds.
  3. C.The antigen-binding site is located at the C-terminal region of antibody molecules.
  4. D.The constant regions of heavy and light chains are located at the C-terminus of antibody molecules.

Solution

Antigen-binding sites lie in the variable regions at the N-terminal ends of the heavy and light chains; the constant regions form the C-terminal end. Statement 3 is the incorrect one.

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Q9openBiotechnology and its Applications · Applications in agriculture: Bt crops, RNAi

Silencing of specific mRNA is possible via RNAi because of:

  1. A.Complementary dsRNA
  2. B.Inhibitory ssRNA
  3. C.Complementary tRNA
  4. D.Non-complementary ssRNA

Solution

RNAi silences a gene through a double-stranded RNA complementary to the target mRNA; the dsRNA is processed into fragments that bind the mRNA and block translation.

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Q10openPrinciples of Inheritance and Variation · Mendel's laws and deviations

Genes R and Y follow independent assortment. If RRYY produces round yellow seeds and rryy produces wrinkled green seeds, what will be the phenotypic ratio of the generation?

  1. A.Phenotypic ratio 1 : 2 : 1
  2. B.Phenotypic ratio 3 : 1
  3. C.Phenotypic ratio 9 : 3 : 3 : 1
  4. D.Phenotypic ratio 9 : 7

Solution

Independent assortment of two genes in a dihybrid cross gives the classical 9 : 3 : 3 : 1 phenotypic ratio in the round yellow : round green : wrinkled yellow : wrinkled green).

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Q11openMolecular Basis of Inheritance · DNA structure and replication

Histones are enriched with:

  1. A.Lysine and arginine
  2. B.Leucine and lysine
  3. C.Phenylalanine and leucine
  4. D.Phenylalanine and arginine

Solution

Histones are rich in the basic amino acids lysine and arginine; their positive charge binds the negatively charged DNA.

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Q12openHuman Reproduction · Gametogenesis and menstrual cycle

The first menstruation is called:

  1. A.Menopause
  2. B.Menarche
  3. C.Diapause
  4. D.Ovulation

Solution

The first menstruation, at puberty, is menarche; the cessation of cycles around age 50 is menopause.

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Q13openChemical Coordination and Integration · Endocrine glands and their hormones

Match List I with List II.

List IList II
A. HeartI. Erythropoietin
B. KidneyII. Aldosterone
C. Gastro-intestinal tractIII. Atrial natriuretic factor
D. Adrenal cortexIV. Secretin

Choose the correct answer from the options given below:

  1. A.A-II, B-I, C-III, D-IV
  2. B.A-IV, B-III, C-II, D-I
  3. C.A-I, B-III, C-IV, D-II
  4. D.A-III, B-I, C-IV, D-II

Solution

The heart's atrial wall secretes ANF (III); the kidney secretes erythropoietin (I); the gut secretes secretin (IV); the adrenal cortex secretes aldosterone (II).

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Q14openBiomolecules · Enzymes: mechanism, factors, classification

The protein portion of an enzyme is called:

  1. A.Cofactor
  2. B.Coenzyme
  3. C.Apoenzyme
  4. D.Prosthetic group

Solution

The protein part of a conjugated enzyme is the apoenzyme; with its cofactor it forms the active holoenzyme.

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Q15openEcosystem · Structure, productivity and decomposition

Which of the following is the unit of productivity of an ecosystem?

  1. A.
  2. B.
  3. C.
  4. D.

Solution

Productivity is the rate of biomass production per unit area per unit time, expressed in or .

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Q16openEvolution · Natural selection, Hardy–Weinberg, adaptive radiation

Sweet potato and potato represent a certain type of evolution. Select the correct combination of terms to explain the evolution.

  1. A.Analogy, convergent
  2. B.Homology, divergent
  3. C.Homology, convergent
  4. D.Analogy, divergent

Solution

Sweet potato (a root) and potato (a stem) look alike and store food but have different origins — analogous structures produced by convergent evolution.

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Q17openPrinciples of Inheritance and Variation · Sex determination, mutation, genetic disorders

With the help of the given pedigree, find out the probability for the birth of a child having no disease and being a carrier (has the disease mutation in one allele of the gene) in the generation.

Question 152 as printed in the NEET 2025 booklet

  1. A.1/4
  2. B.1/2
  3. C.1/8
  4. D.Zero

Solution

The pedigree fits X-linked recessive inheritance (affected mother → all daughters carriers; carrier mother → affected son). The cross is carrier female × affected male : offspring (carrier daughter), (affected daughter), (normal son), (affected son), each 1/4. Probability of a disease-free carrier is 1/4.

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Q18openSexual Reproduction in Flowering Plants · Flower structure, microsporogenesis and megasporogenesis

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A): Cells of the tapetum possess dense cytoplasm and generally have more than one nucleus.

Reason (R): The presence of more than one nucleus in the tapetum increases the efficiency of nourishing the developing microspore mother cells.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both A and R are true and R is the correct explanation of A
  2. B.Both A and R are true but R is NOT the correct explanation of A
  3. C.A is true but R is false
  4. D.A is false but R is true

Solution

Tapetal cells are multinucleate with dense cytoplasm (A true), and this polyploid, multinucleate state supports their role of nourishing the developing microspores (R true, and it explains A).

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Q19openSexual Reproduction in Flowering Plants · Flower structure, microsporogenesis and megasporogenesis

How many meiotic and mitotic divisions need to occur for the development of a mature female gametophyte from the megaspore mother cell in an angiosperm plant?

  1. A.2 meiosis and 3 mitosis
  2. B.1 meiosis and 2 mitosis
  3. C.1 meiosis and 3 mitosis
  4. D.No meiosis and 2 mitosis

Solution

One meiosis of the megaspore mother cell gives four megaspores; the surviving one undergoes three mitotic divisions to form the 8-nucleate embryo sac. So 1 meiosis and 3 mitoses.

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Q20openMorphology of Flowering Plants · Inflorescence, flower and floral formula

Which of the following is an example of a zygomorphic flower?

  1. A.Petunia
  2. B.Datura
  3. C.Pea
  4. D.Chilli

Solution

Pea (Fabaceae) has a zygomorphic papilionaceous flower. Petunia, Datura and chilli (Solanaceae) have actinomorphic flowers.

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Q21openHuman Health and Disease · Immunity, vaccination, AIDS, cancer

After maturation in primary lymphoid organs, lymphocytes migrate for interaction with antigens to secondary lymphoid organ(s)/tissue(s) like:

A. thymus · B. bone marrow · C. spleen · D. lymph nodes · E. Peyer's patches

Choose the correct answer from the options given below:

  1. A.B, C, D only
  2. B.A, B, C only
  3. C.E, A, B only
  4. D.C, D, E only

Solution

Thymus and bone marrow are the primary lymphoid organs where lymphocytes mature. They then migrate to the secondary lymphoid organs — spleen, lymph nodes, tonsils, Peyer's patches and appendix — to meet antigens. Hence C, D and E.

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Q22openOrganisms and Populations · Population attributes, growth models and interactions

Given below are two statements:

Statement I: The fig fruit is a non-vegetarian fruit as it has enclosed fig wasps in it.

Statement II: The fig wasp and fig tree exhibit a mutual relationship, as the fig wasp completes its life cycle in the fig fruit and the fig fruit gets pollinated by the fig wasp.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both Statement I and Statement II are correct
  2. B.Both Statement I and Statement II are incorrect
  3. C.Statement I is correct but Statement II is incorrect
  4. D.Statement I is incorrect but Statement II is correct

Solution

The official key marks both statements incorrect: the fig is a syconium (an inflorescence, not a true fruit) and the wasp inside it does not make it 'non-vegetarian'; and while fig and wasp are indeed mutualists, the statement as framed — the wasp completing its life cycle in a 'fruit' — was not accepted.

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Q23openCell Cycle and Cell Division · Mitosis

What is the main function of the spindle fibres during mitosis?

  1. A.To separate the chromosomes
  2. B.To synthesise new DNA
  3. C.To repair damaged DNA
  4. D.To regulate cell growth

Solution

Spindle fibres attach to kinetochores and pull the sister chromatids apart to opposite poles during anaphase.

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Q24openPlant Kingdom · Gymnosperms and angiosperms; alternation of generations

Which one of the following is the characteristic feature of gymnosperms?

  1. A.Seeds are enclosed in fruits
  2. B.Seeds are naked
  3. C.Seeds are absent
  4. D.Gymnosperms have flowers for reproduction

Solution

Gymnosperms bear naked seeds on megasporophylls; the ovules are not enclosed in an ovary, so there is no fruit.

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Q25openChemical Coordination and Integration · Endocrine glands and their hormones

Consider the following statements regarding the functions of adrenal medullary hormones:

(A) They cause pupillary constriction.

(B) They are hyperglycaemic hormones.

(C) They cause piloerection.

(D) They increase the strength of heart contraction.

Choose the correct answer from the options given below:

  1. A.C and D only
  2. B.B, C and D only
  3. C.A, C and D only
  4. D.D only

Solution

Adrenaline and noradrenaline raise blood glucose (B), cause piloerection (C) and increase the force of heart contraction (D). They dilate the pupils, so A is wrong. Hence B, C and D.

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Q26openBiotechnology and its Applications · Applications in medicine: insulin, gene therapy, molecular diagnosis

Why can't insulin be given orally to diabetic patients?

  1. A.The human body will elicit a strong immune response
  2. B.It will be digested in the gastro-intestinal (GI) tract
  3. C.Because of structural variation
  4. D.Its bioavailability will be increased

Solution

Insulin is a peptide hormone; taken by mouth it would be digested by gastric and pancreatic proteases before it could act, so it must be injected.

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Q27openPlant Kingdom · Bryophytes and pteridophytes

Match List I with List II.

List IList II
A. PteridophyteI. Salvia
B. BryophyteII. Ginkgo
C. AngiospermIII. Polytrichum
D. GymnospermIV. Salvinia

Choose the option with all correct matches:

  1. A.A-III, B-IV, C-II, D-I
  2. B.A-IV, B-III, C-I, D-II
  3. C.A-III, B-IV, C-I, D-II
  4. D.A-IV, B-III, C-II, D-I

Solution

Salvinia is a pteridophyte (IV); Polytrichum a moss, i.e. bryophyte (III); Salvia an angiosperm (I); Ginkgo a gymnosperm (II).

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Q28openMolecular Basis of Inheritance · Transcription, genetic code, translation

Who proposed that the genetic code for amino acids should be made up of three nucleotides?

  1. A.George Gamow
  2. B.Francis Crick
  3. C.Jacques Monod
  4. D.Franklin Stahl

Solution

George Gamow, a physicist, argued that a code for 20 amino acids using four bases must be a triplet code, since combinations suffice while do not.

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Q29openBiodiversity and Conservation · Loss of biodiversity and its conservation

Match List I with List II.

List IList II
A. The Evil QuartetI. Cryopreservation
B. Ex-situ conservationII. Alien species invasion
C. Lantana camaraIII. Causes of biodiversity losses
D. DodoIV. Extinction

Choose the option with all correct matches:

  1. A.A-III, B-II, C-I, D-IV
  2. B.A-III, B-I, C-II, D-IV
  3. C.A-III, B-IV, C-II, D-I
  4. D.A-III, B-II, C-IV, D-I

Solution

The Evil Quartet names the causes of biodiversity loss (III); cryopreservation is an ex-situ method (I); Lantana camara is an invasive alien species (II); the dodo is the classic extinction (IV).

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Q30openChemical Coordination and Integration · Endocrine glands and their hormones

Which of the following hormones released from the pituitary is actually synthesised in the hypothalamus?

  1. A.Luteinising hormone (LH)
  2. B.Anti-diuretic hormone (ADH)
  3. C.Follicle-stimulating hormone (FSH)
  4. D.Adrenocorticotropic hormone (ACTH)

Solution

ADH (vasopressin) and oxytocin are synthesised by hypothalamic neurons and only stored and released by the posterior pituitary. LH, FSH and ACTH are made in the anterior pituitary itself.

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Q31openAnimal Kingdom · Non-chordates: Porifera to Echinodermata

The role of the water vascular system in echinoderms is:

A. Respiration and locomotion

B. Excretion and locomotion

C. Capture and transport of food

D. Digestion and respiration

E. Digestion and excretion

Choose the correct answer from the options given below:

  1. A.A and B only
  2. B.A and C only
  3. C.B and C only
  4. D.B, D and E only

Solution

The echinoderm water vascular system, with its tube feet, serves locomotion, capture and transport of food, and respiration — statements A and C. It plays no part in excretion or digestion.

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Q32openHuman Health and Disease · Immunity, vaccination, AIDS, cancer

Which of the following types of immunity is present at the time of birth and is a non-specific type of defence in the human body?

  1. A.Acquired immunity
  2. B.Innate immunity
  3. C.Cell-mediated immunity
  4. D.Humoral immunity

Solution

Innate immunity is present from birth and is non-specific: physical, physiological, cellular and cytokine barriers. Acquired immunity is specific and develops after exposure.

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Q33openPlant Kingdom · Bryophytes and pteridophytes

In bryophytes, the gemmae help in which one of the following?

  1. A.Sexual reproduction
  2. B.Asexual reproduction
  3. C.Nutrient absorption
  4. D.Gaseous exchange

Solution

Gemmae are green, multicellular buds formed in gemma cups on the thallus of liverworts such as Marchantia; they detach and grow into new plants — asexual reproduction.

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Q34openStructural Organisation in Animals · Frog: morphology and anatomy

In the frog, the renal portal system is a special venous connection that acts to link:

  1. A.Liver and intestine
  2. B.Liver and kidney
  3. C.Kidney and intestine
  4. D.Kidney and lower part of the body

Solution

The frog's renal portal system carries venous blood from the hind limbs and lower body to the kidneys before it returns to the heart.

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Q35openEcosystem · Energy flow, ecological pyramids

Given below are two statements:

Statement I: In an ecosystem, there is a unidirectional flow of the energy of the sun from producers to consumers.

Statement II: Ecosystems are exempted from the 2nd law of thermodynamics.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both Statement I and Statement II are correct
  2. B.Both Statement I and Statement II are incorrect
  3. C.Statement I is correct but Statement II is incorrect
  4. D.Statement I is incorrect but Statement II is correct

Solution

Energy from the sun flows one way through an ecosystem, from producers to consumers (I correct). Ecosystems obey the laws of thermodynamics; energy is lost as heat at every transfer, which is the second law at work (II incorrect).

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Q36openPhotosynthesis in Higher Plants · Calvin cycle, C4 pathway, photorespiration

Which of the following statements about RuBisCO is true?

  1. A.It is active only in the dark
  2. B.It has a higher affinity for oxygen than for carbon dioxide
  3. C.It is an enzyme involved in the photolysis of water
  4. D.It catalyses the carboxylation of RuBP

Solution

RuBisCO catalyses the carboxylation of RuBP in the Calvin cycle. It is active in light, has a higher affinity for than for , and has nothing to do with photolysis of water.

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Q37openBiotechnology: Principles and Processes · Tools of recombinant DNA technology

Which of the following enzymes are not essential for gene cloning?

A. Restriction enzymes · B. DNA ligase · C. DNA mutase · D. DNA recombinase · E. DNA polymerase

Choose the correct answer from the options given below:

  1. A.C and D only
  2. B.A and B only
  3. C.D and E only
  4. D.B and C only

Solution

Gene cloning needs restriction enzymes to cut, DNA ligase to join and DNA polymerase for PCR. 'DNA mutase' and 'DNA recombinase' are not part of the toolkit. Hence C and D.

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Q38openPlant Growth and Development · Plant growth regulators: auxin, gibberellin, cytokinin, ethylene, ABA

Read the following statements on plant growth and development.

(A) Parthenocarpy can be induced by auxins.

(B) Plant growth regulators can be involved in the promotion as well as the inhibition of growth.

(C) Dedifferentiation is a pre-requisite for redifferentiation.

(D) Abscisic acid is a plant growth promoter.

(E) Apical dominance promotes the growth of lateral buds.

Choose the option with all correct statements:

  1. A.A, B, C only
  2. B.A, C, E only
  3. C.A, D, E only
  4. D.B, D, E only

Solution

Auxins induce parthenocarpy (A); growth regulators can promote or inhibit growth (B); cells must dedifferentiate before they can redifferentiate (C). Abscisic acid is a growth inhibitor, and apical dominance suppresses lateral buds. Hence A, B and C.

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Q39openMolecular Basis of Inheritance · Transcription, genetic code, translation

Which factor is important for the termination of transcription?

  1. A.alpha)
  2. B.sigma)
  3. C.rho)
  4. D.gamma)

Solution

In prokaryotes the rho factor binds the growing RNA and terminates transcription; the sigma factor is needed for initiation.

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Q40openStructural Organisation in Animals · Frog: morphology and anatomy

Frogs respire in water by the skin and buccal cavity, and on land by the skin, buccal cavity and lungs. Choose the correct answer from the following:

  1. A.The statement is true for water but false for land
  2. B.The statement is true for both environments
  3. C.The statement is false for water but true for land
  4. D.The statement is false for both environments

Solution

In water the frog breathes only through its skin (cutaneous respiration); on land it uses the skin, the buccal cavity and the lungs. So the statement is false for water but true for land.

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Q41openHuman Reproduction · Fertilisation, implantation, pregnancy, parturition, lactation

Twins are born to a family that lives next door to you. The twins are a boy and a girl. Which of the following must be true?

  1. A.They are monozygotic twins.
  2. B.They are fraternal twins.
  3. C.They were conceived through in vitro fertilisation.
  4. D.They have 75% identical genetic content.

Solution

Twins of different sexes must have come from two separate zygotes — they are dizygotic (fraternal) twins, genetically no more alike than ordinary siblings.

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Q42openMicrobes in Human Welfare · Microbes in household and industrial products

Which of the following microbes are not involved in the preparation of household products?

A. Aspergillus niger · B. Lactobacillus · C. Trichoderma polysporum · D. Saccharomyces cerevisiae · E. Propionibacterium sharmanii

Choose the correct answer from the options given below:

  1. A.A and B only
  2. B.A and C only
  3. C.C and D only
  4. D.C and E only

Solution

Lactobacillus (curd), Saccharomyces cerevisiae (bread, beverages) and Propionibacterium sharmanii (Swiss cheese) are household microbes. Aspergillus niger (citric acid) and Trichoderma polysporum (cyclosporin A) are industrial. Hence A and C.

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Q43openChemical Coordination and Integration · Endocrine glands and their hormones

Match List I with List II.

List IList II
A. ProgesteroneI. Pars intermedia
B. RelaxinII. Ovary
C. Melanocyte-stimulating hormoneIII. Adrenal medulla
D. CatecholaminesIV. Corpus luteum

Choose the correct answer from the options given below:

  1. A.A-IV, B-II, C-I, D-III
  2. B.A-IV, B-II, C-III, D-I
  3. C.A-II, B-IV, C-I, D-III
  4. D.A-III, B-II, C-IV, D-I

Solution

Progesterone comes from the corpus luteum (IV); relaxin from the ovary (II); melanocyte-stimulating hormone from the pars intermedia (I); catecholamines from the adrenal medulla (III).

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Q44openBiotechnology: Principles and Processes · Tools of recombinant DNA technology

Blue and white selectable markers have been developed which differentiate recombinant colonies from non-recombinant colonies on the basis of their ability to produce colour in the presence of a chromogenic substrate. Given below are two statements about this method:

Statement I: The blue-coloured colonies have the DNA insert in the plasmid and they are identified as recombinant colonies.

Statement II: The colonies without blue colour have the DNA insert in the plasmid and are identified as recombinant colonies.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A.Both Statement I and Statement II are correct
  2. B.Both Statement I and Statement II are incorrect
  3. C.Statement I is correct but Statement II is incorrect
  4. D.Statement I is incorrect but Statement II is correct

Solution

An insert in the lacZ gene destroys galactosidase, so recombinant colonies cannot turn the chromogenic substrate blue — recombinants are the white colonies. Statement I is wrong, Statement II is correct.

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Q45openOrganisms and Populations · Population attributes, growth models and interactions

Which one of the following equations represents the Verhulst–Pearl logistic growth of a population?

  1. A.
  2. B.
  3. C.
  4. D.

Solution

The Verhulst–Pearl logistic equation is , growth slowing as the population approaches the carrying capacity .

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